$\begin{align*} \int \frac{dx}{\sqrt{x} (x+9)} \end{align*}$ is equal to :

Question

( A ) $\tan^{-1} (\frac{\sqrt{x}}{3}) +c$
( B ) $\frac{2}{3} \tan^{-1} (\sqrt{x}) +c$
( C ) $\frac{2}{3} \tan^{-1} (\frac{\sqrt{x}}{3}) +c$
( D ) $\tan^{-1} (\sqrt{x}) +c$