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JEEMAIN and NEET
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JEEMAIN PAST PAPERS
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2001
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Q)
$20^{2-3x^2} = (40\sqrt{5})^{3x^2-2}$, then $x$ is equal to :
( A ) $\pm \frac{\sqrt{4}}{3}$
( B ) $\pm \frac{\sqrt{3}}{2}$
( C ) $\pm \frac{\sqrt{2}}{3}$
( D ) $\pm \frac{\sqrt{5}}{4}$
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