Email
Chat with tutors
Login
Ask Questions, Get Answers
Menu
X
home
ask
tuition
questions
practice
papers
mobile
tutors
pricing
X
Questions
>>
JEEMAIN and NEET
>>
JEEMAIN PAST PAPERS
>>
2001
Next similar question
Answer
Comment
Share
Q)
Each of the roots of the equation $x^3 - 6x^2 + 6x-5 =0$ are increased by $h$. So that the new transformed equation does not contain $x^2$ term, then $h$ is equal to :
( A ) $2$
( B ) $\frac{1}{3}$
( C ) $\frac{1}{2}$
( D ) $1$
Share
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
Next Similar Question >
Home
Ask
Tuition
Questions
Practice
Your payment for
is successful.
Continue
...