If $\theta = \frac{\pi}{6}$, then the $10^{th}$ term of $1 + (\cos \theta + i \sin \theta) +(\cos \theta + i \sin \theta)^2+(\cos \theta + i \sin \theta)^3 + ... $ is equal to :

Question

( A ) $i$
( B ) $-i$
( C ) $-1$
( D ) $1$