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∫
e
x
(
1
+
cot
x
+
cot
2
x
)
d
x
is equal to :
( A )
e
x
c
o
s
e
c
x
+
c
( B )
e
x
cot
x
+
c
( C )
−
e
x
cot
x
+
c
( D )
−
e
x
c
o
s
e
c
x
+
c
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