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Q)
Summation
n
∑
k
=
1
k
[
1
+
1
n
]
k
−
1
is equal to :
( A )
n
(
n
+
1
)
( B )
n
(
n
−
1
)
( C )
(
n
+
1
)
2
( D )
n
2
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