$\begin{bmatrix} \frac{\sqrt{3} + 2 \cos A}{1- 2 \sin A} \end{bmatrix}^3 + \begin{bmatrix} \frac{1 + 2 \sin A}{\sqrt{3} - 2 \cos A} \end{bmatrix}^3$ is equal to :

Question

( A ) $1$
( B ) $\sqrt{3}$
( C ) $0$
( D ) $-1$