If $\tan \theta + \sec \theta = \sqrt{3}$, then the principal value of $\theta + \frac{\pi}{6}$ is equal to :

Question

( A ) $\frac{\pi}{3}$
( B ) $\frac{3 \pi}{4}$
( C ) $\frac{2\pi}{3}$
( D ) $\frac{\pi}{4}$