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JEEMAIN and NEET
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JEEMAIN PAST PAPERS
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1999
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Q)
The general solution of
tan
2
θ
=
3
is :
( A )
n
π
±
π
3
( B )
n
π
+
(
−
1
)
n
π
3
( C )
2
n
π
+
(
−
1
)
n
π
3
( D )
2
n
π
±
π
3
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