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If the position vectors of $\overrightarrow{A} $ and $\overrightarrow{B}$ are $3 \hat{i} - 2 \hat{j} + \hat{k}$ and $2 \hat{i} + 4\hat{j} - 3\hat{k}$, then $|\overrightarrow{AB}|$ is equal to :


( A ) $\sqrt{43}$
( B ) $\sqrt{53}$
( C ) $\sqrt{29}$
( D ) $\sqrt{14}$

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