Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

The locus of point of intersection of perpendicular tangents to the circle $x^2+y^2=a^2$ is:


( A ) $x^2+y^2=8a^2$
( B ) $x^2 + y^2 = 4a^2$
( C ) $x^2 + y^2 = 2a^2$
( D ) $x^2+y^2=6a^2$

Please log in or register to answer this question.

Home Ask Tuition Questions
Your payment for is successful.
Continue
...