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JEEMAIN and NEET
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JEEMAIN PAST PAPERS
>>
1998
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Q)
One of the focii of hyperbola is origin and the corresponding directrix is
3
x
+
4
y
+
1
=
0
. The eccentricity of the hyperbola is
√
5
. The equation to the hyperbola is :
( A )
8
x
2
+
9
y
2
+
24
x
y
+
6
x
+
6
y
+
1
=
0
( B )
8
x
2
+
9
y
2
+
24
x
y
+
6
x
+
8
y
+
1
=
0
( C )
8
x
2
+
15
y
2
+
24
x
y
+
6
x
+
8
y
+
1
=
0
( D )
8
x
2
+
9
y
2
−
24
x
y
+
6
x
+
8
y
+
1
=
0
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