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1998
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Q)
The solution of the differential equation $\frac{dy}{dx} - \frac{2xy}{1+x^2}=0$ is :
( A ) $y = A\sqrt{1+x^2}$
( B ) $Y = \frac{A}{\sqrt{1+x^2}}$
( C ) $Y = \frac{A}{(1+x^2)}$
( D ) $y = A (1+x^2)$
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