$\begin{align*} \int \frac{x^5}{x^2 + 1} \;dx \end{align*}$ is equal to :

Question

( A ) $\frac{x^4}{4} - \frac{x^2}{2} + \frac{1}{2} \log (x^2 + 1) + c$
( B ) $\frac{x^4}{4} + \frac{x^2}{2} + \tan^{-1}x+c$
( C ) $\frac{x^4}{4} + \frac{x^2}{3} - \tan^{-1}x+c$
( D ) $\frac{x^4}{4} + \frac{x^2}{3} + \tan^{-1}x+c$