$\begin{align*} \int \frac{e^x (1+x \log x)}{x}\;dx \end{align*}$ is equal to :

Question

( A ) $\frac{e^x \log x}{x} +c$
( B ) $e^x(1+ \log x)+c$
( C ) $xe^x \log x +c$
( D ) $e^x \log x +c$