The anti derivative of $\bigg(\sqrt x+\frac{1}{\sqrt x}\bigg)$ equals

Question

$\begin{array}{1 1} (A)\;\frac{1}{3}x^{\frac{1}{3}}+2x^{\frac{1}{2}}+C \\ (B)\;\frac{2}{3}x^{\frac{2}{3}}+\frac{1}{2}x^2+C\\(C)\;\frac{2}{3}x^{\frac{3}{2}}+2x^{\frac{1}{2}}+C \\ (D)\;\frac{3}{2}x^{\frac{3}{2}}+\frac{1}{2}x^{\frac{1}{2}}+C\end{array}$