Find the integral $\int\sqrt x\;(3x^2+2x+3)\;dx$

Question

$\begin{array}{1 1}\frac{6}{7}x^\frac{7}{2}+\frac{4}{5}x^\frac{5}{2}+2x^\frac{3}{2}+c. \\ \frac{6}{5}x^\frac{5}{2}-\frac{4}{3}x^\frac{3}{2}-2x^\frac{1}{2}+c. \\ \frac{6}{5}x^\frac{5}{2}+\frac{4}{3}x^\frac{3}{2}+2x^\frac{1}{2}+c. \\ \frac{6}{7}x^\frac{7}{2}-\frac{4}{5}x^\frac{5}{2}-2x^\frac{3}{2}+c. \end{array}$