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$\large\frac{x^2+x+1}{(x-1)(x-2)(x-3)}=\frac{A}{x-1}+\frac{B}{x-2}+\frac{C}{x-3}$ then find $A+C=$
\[\begin {array} {1 1} (a)\;4 & \quad (b)\;5 \\ (c)\;6 & \quad (d)\;8 \end {array}\]
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