If $x > -1$ which of the following is equivalent to $\large\frac{1}{x+1}+\frac{2x+1}{3}$

Question

$\begin{array}{1 1} (a)\;\large\frac{2x^2+3x+4}{3x+3} \\ (b)\;\large\frac{3(x+1)}{2x^2+3x+4} \\(c)\;2x^2+3x+4 \\(d)\;3(x+1) \end{array} $