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5×2_2xy+5y2+2x_10y_7=0
5×2_2xy+5y2+2x_10y_7=0
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the complete question should be
Show that if the origin is transferred to (0,1) and the axes are rotated
through 45°, the equation 5×2_2xy+5y2+2x_10y_7=0referred
x,2 y,2
to new axes becomes x^2/3 +y^2/2 = 1.
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