$a \sin ^2 \theta+ b \cos ^2 \theta=c=>\tan ^2 \theta=$

Question

$$\begin {array} {1 1} (1)\;\frac{b-c}{a-c} & \quad (2)\;\frac{c-b}{a-c} \\ (3)\;\frac{a-c}{b-c} & \quad (4)\;\frac{a-c}{c-b} \end {array}$$