If $t_n=\bigg(1+\large\frac{1}{n}\bigg)$$^n$ for $n\in N$, then $t_n$ lies in the interval?

Question

$\begin{array}{1 1} 1 \leq t_n < 2 \\ 2 \leq t_n 3 \\ 2 < t_n \leq 3 \\ t_n > 3 \end{array}$