If $A$ lies in the third quadrant and $3 \tan A-4=0$ then $5\sin 2A+3\sin A+4\cos A$ is equal to

Question

$(a)\;0\qquad(b)\;\large\frac{-24}{5}$$\qquad(c)\;\large\frac{24}{5}$$\qquad(d)\;\large\frac{48}{5}$