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Q)
If
I
n
=
∫
sin
n
x
d
x
, then
n
I
n
−
(
n
−
1
)
I
n
−
2
=
(
1
)
sin
n
−
1
x
cos
x
(
2
)
cos
n
−
1
x
sin
x
(
3
)
−
sin
n
−
1
x
cos
x
(
4
)
−
cos
n
−
1
x
sin
x
Share
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