Email
Chat with tutors
Login
Ask Questions, Get Answers
Menu
X
home
ask
tuition
questions
practice
papers
mobile
tutors
pricing
X
Questions
>>
CBSE XI
>>
Chemistry
>>
Structure of Atom
Next similar question
Answer
Comment
Share
Q)
A 1 MeV proton is sent against a gold leaf (Z = 79). Calculate the distance of closest approach for head on collision.
(
a
)
1.137
×
10
−
13
m
(
b
)
2.137
×
10
−
13
m
(
c
)
3.137
×
10
−
13
m
(
d
)
4.137
×
10
−
13
m
Share
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
Found
1
answer. Click to login & view.
Next Similar Question >
Home
Ask
Tuition
Questions
Practice
Your payment for
is successful.
Continue
...
Please Wait