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NEET PAST PAPERS
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2019
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Q)
For a cell involving one electron$ E^\ominus$ cell = 0.59V at 298 K, the equilibrium constant for the cell reaction is :- $\bigg[Given \;that \frac{2.303RT}{F}=0.059V \;at \;T=298k\bigg]$
( A ) $1.0\times 10^{5}$
( B ) $1.0\times 10^{10}$
( C ) $1.0\times 10^{2}$
( D ) $1.0\times 10^{30}$
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