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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2019
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Q)

For a cell involving one electron$ E^\ominus$ cell = 0.59V at 298 K, the equilibrium constant for the cell reaction is :- $\bigg[Given \;that \frac{2.303RT}{F}=0.059V \;at \;T=298k\bigg]$


( A ) $1.0\times 10^{5}$
( B ) $1.0\times 10^{10}$
( C ) $1.0\times 10^{2}$
( D ) $1.0\times 10^{30}$

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