For the chemical reaction $N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$ the correct option is :

Question

( A ) $-\frac{1}{d}\frac{d[H_2]}{dt}=-\frac{1}{2}\frac{d[NH_3]}{dt}$
( B ) $-\frac{d[N_2]}{dt}=2\frac{d[NH_3]}{dt}$
( C ) $\frac{d[N_2]}{dt}=\frac{1}{2}\frac{d[NH_3]}{dt}$
( D ) $3\frac{d[H_2]}{dt}=2\frac{d[NH_3]}{dt}$