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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2019
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Q)

A force $F = 20 + 10y$ acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from $y = 0$ to $y = 1;m$ is :


( A ) 30 J
( B ) 5 J
( C ) 25 J
( D ) 20 J

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