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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2019
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An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly):(mc=9×1031kg)


( A ) 12.2×1014m
( B ) 12.2×1013m
( C ) 12.2×1012m
( D ) 12.2 nm
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