A small hole of area of cross-section $2 mm^2$ is present near the bottom of a fully filled open tank of height 2m. Taking g = $10\frac{ m}{s^2}$, the rate of flow of water through the open hole would be nearly :

Question

( A ) $12.6 \times 10^{-6}m^\frac{3}{s}$
( B ) $8.9 \times 10^{-6}m^\frac{3}{s}$
( C ) $2.23 \times 10^{-6}m^\frac{3}{s}$
( D ) $6.4 \times 10^{-6}m^\frac{3}{s}$