The Edison storage cell is represented as Fe(s)/FeO(s)/KOH(aq)/Ni2O3(s)/Ni(s).The half cell reactions are Ni2O3(s)+H2O(l)+2e−→2NiO(s)+2OH−(aq)⇒E0=0.4V,FeO(s)+H2O(l)+2e−→Fe(s)+2OH−(aq)⇒E0=−0.87.V
How much electrical energy can be obtained per kilogram of the active materials in the cell?
