$\begin{array}{1 1}(a)\;\tan^2x=0&(b)\;\large\frac{\sin^8x}{8}+\frac{\cos^8x}{27}=\frac{1}{125}\\(c)\;\tan^2x=\large\frac{1}{3}&(d)\;\large\frac{\sin^8x}{8}+\frac{\cos^8x}{27}=\frac{2}{125}\end{array}$
