4NO2(g)+O2(g)→2N2O5(g),ΔH=111kj if N2O5(s) is formed instead of N2O5(g), the ΔH value in kj is : (ΔHsublimation for N2O5=54kjmol−1)
(1)−165(2)−57(3)+219(4)−219