$4NO_{2_{(g)}}+ O_{2_{(g)}} \rightarrow 2N_2O_{5_{(g)}}, \: \: \: \Delta H=111kj$
if $N_2O_{5_{(s)}}$ is formed instead of $N_2O_{5_{(g)}}$, the $ \Delta H$ value in $kj$ is :
$( \Delta H_{sublimation}$ for $ N_2O_5=54\: kj\: mol^{-1})$
$\begin {array} {1 1} (1)\;-165 & \quad (2)\;-57 \\ (3)\;+219 & \quad (4)\;-219 \end {array}$
