KIO3+5KI+6HCI→3I2+6KCI+3H2O (1) I is reduced to I2 (2) IO3 is oxidized to I2 (3) IO3 is reduced to I2 (4) Oxidation number of I increases from −I(inKI) to zero (inI2) The correct statement are
(1)1,2and4(2)3and4(3)1and4(4)1,3and4