$KIO_3+5KI+6HCI \rightarrow 3I_2 +6KCI+3H_2O$
(1) $I $ is reduced to $I_2$
(2) $IO_3$ is oxidized to $I_2$
(3) $IO_3$ is reduced to $I_2$
(4) Oxidation number of $I$ increases from $ -I \: ( in\: KI)$ to zero $ ( in\: I_2)$
The correct statement are
$\begin {array} {1 1} (1)\;1,2 \: and \: 4 & \quad (2)\;3\: and \: 4 \\ (3)\;1\: and \: 4 & \quad (4)\;1,3\: and \: 4 \end {array}$
