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Q)
If
f
:
[
−
6
,
6
]
→
ℜ
is defined by
f
(
x
)
=
x
2
−
3
for
x
∈
ℜ
, then
(
f
0
f
0
f
)
(
−
l
)
+
(
f
0
f
0
f
)
(
0
)
+
(
f
0
f
0
f
)
(
l
)
=
(
1
)
f
(
4
√
2
)
(
2
)
f
(
3
√
2
)
(
3
)
f
(
2
√
2
)
(
4
)
f
(
√
2
)
Share
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