In Rutherford scattering experiment, an $\alpha$ particle is projected with $KE=4MeV$ , maximum distance up to which this $\alpha$ particle can reach to the nucleus of Cu nucleus : (atomic number of Cu= 29)

Question

$\begin{array}{1 1}(a)\; 2.08 \times 10^{-14} \;m \\ (b)\;2.08 \times 10^{-15} \;m \\ (c) \;1.04 \times 10^{-14} \;m \\ (d)\;0.04 \times 10^{-15} \;m\end{array} $