The value of $2 \cos 6A-2 \cos 2A-1$ is equal to

Question

$\begin{array}{1 1} \large\frac{\cos 7A}{\cos A} \\ \large\frac{\cos 6A}{\cos A} \\ \large\frac{\cos 5A}{\cos A} \\ \large\frac{\cos 4A}{\cos A} \end{array} $