From the top of a hill the angles of depression of the top and the bottom of a pillar are $\alpha$ and $\beta$ respectively. The height (in meters) of the pillar is

Question

$$\begin {array} {1 1} (1)\;\frac{h(\tan \beta- \tan \alpha)}{\tan \beta} & \quad (2)\;\frac{h(\tan \alpha- \tan \beta)}{\tan \alpha} \\ (3)\;\frac{h(\tan \beta + \tan \alpha)}{\tan \beta} & \quad (4)\;\frac{h(\tan \beta + \tan \alpha)}{\tan \alpha} \end {array}$$