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Q)
If the lines
2
x
−
3
y
=
5
and
3
x
−
4
y
=
7
are two diameters of a circle of radius 7, then the equation of the circle is
(
1
)
x
2
+
y
2
+
2
x
−
4
y
−
47
=
0
(
2
)
x
2
+
y
2
=
49
(
3
)
x
2
+
y
2
−
2
x
+
2
y
−
47
=
0
(
4
)
x
2
+
y
2
=
17
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