If $f(2)=4$ and $f'(2)=1$, then $\lim \limits_{x \to 2} \large\frac{x f(2) -2 f(x)}{x-2}=$

Question

\[\begin {array} {1 1} (1)\;-2 & \quad (2)\;1 \\ (3)\;2 & \quad (4)\;3 \end {array}\]