The value of $\large\frac{\sec 8\theta-1}{\sec 4\theta-1}$ is equal to

Question

$\begin{array}{1 1}(a)\;\large\frac{\tan 2\theta}{\tan 8\theta}&(b)\;\large\frac{\tan 8\theta}{\tan 4\theta}\\(c)\;\large\frac{\tan 8\theta}{\tan 2\theta}&(d)\;\large\frac{\tan 6\theta}{\tan 2\theta}\end{array}$