The solution of the different equation $\large\frac{dy}{dx}=\frac{xy+y}{xy+x}$ is

Question

\[\begin {array} {1 1} (1)\;x+y= \log \bigg(\frac{Cy}{x} \bigg) \\ (2)\;x+y-log (Cxy) \\ (3)\;x-y= \log \bigg(\frac{Cx}{y}\bigg)\\ (4)\;y-x-\log \bigg(\frac{Cx}{y}\bigg) \end {array}\]