Volume of a cone is $\dfrac{1}{3} \pi r^2h$. What will be its height in terms of $v$ and $r$ ?

Question

$\begin{array}{1 1} (a)\;h=\dfrac{3r^2}{\pi v} \\ (b)\; h=\dfrac{3v}{\pi r^2} \\ (c)\; h=\dfrac{vr^2}{3\pi}\\ (d)\;h= \dfrac{3 \pi}{vr^2} \end{array}$