$\begin{align*}\frac{48 x^2d^2y}{-12 x^6dy^3} =\end{align*}$

Question

$\begin{array}{1 1} (a)\;\frac{-3dy^2}{x^3}\\(b)\; \frac{-3d}{x^4y^2} \\(c)\; \frac{-3d^2x^3}{y}\\(d)\;\frac{-3d}{x^3y} \end{array}$