Ryan has a bag containing 12 marbles. 4 are red, 4 are blue and 4 are yellow. What is the probability of Ryan drawing out of the bag first a blue marble and then a yellow, if he doesn't replace the first marble he drew ?

Question

$\begin{array}{1 1} (a)\; \frac{4}{12}\\ (b)\; \frac{16}{33} \\ (c)\;\frac{16}{12} \\ (d)\; \frac{4}{33} \end{array}$