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Q)
If
∫
e
x
−
1
e
x
+
1
d
x
=
f
(
x
)
+
c
, then f(x) is equal to
(
a
)
2
log
(
e
x
+
1
)
(
b
)
log
(
e
2
x
−
1
)
(
c
)
2
log
(
e
x
+
1
)
−
x
(
d
)
log
(
e
2
x
+
1
)
Share
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