175. If H, + 0,→HO;AH-- 68.39 kCal K + H,O + water KOH(ag) + 2 H, AH --48.0 kCal KOH + water → KOH (ag) AH -- 14.0 kCal the heat of formation of KOH is- (1)- 68.39 + 48-14.0 (2) – 68.39 - 48.0 +14.0 (3) +68.39-48.0 + 14.0 (4) + 68.39 + 48.0- 14.0

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