Q)
(chatquestion)...Illustration 11. Atom A is every element of FCC, atom B is present at every Octahedral void, atom C is prese
3 x2R= 2
25% of Tetrahedral void. Find out the possible molecular formula of the compound ?
Atom A is every element of FCC = 4 atoms of A
Solution.
3x 2R
Atom B is present at every octahedral void = 4 atoms of B
2R
B-4
noot
Ay ByC2
Atom C is present at 25% of tetrahedral void = 8x-
25
2 atoms of C
%3D
100
So, the possible molecular formula is A, B, C, = A, B, C.
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