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Calculate the number of atoms of oxygen present in 88g $CO_2$.What would be the weight of CO having the same no of oxygen atoms ?

$\begin{array}{1 1}(a)\;23.1\times 10^{23}O_2,110g\;CO\\(b)\;24.092\times 10^{23}O_2,112g\;CO\\(c)\;22.03\times 10^{22}O_2,115g\;CO\\(d)\;1.11\times 10^{20}O_2,120g\;CO\end{array}$

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