Q)
(chatquestion)...WB=2g, K, =4.9K kg mol-,
WA=25g, AT; =1.62K
W3 1000
м, WA
AT;=K÷x-
4.9x2x1000
M3
=241.98g mol
1.62x25
2C,Н,СООН (С Н.СООН),
if 'x' is degree of association then we would have (1-x) mol of Benzoic acid left
undissociated and corresponding x/2 as associated moles of Benzoic acid at
equilibrium. Therefore, total number of moles of particles at equilibrium is
1-x+=1-
122
Normal molecular mass
Abnormal molecular mass
241.98
122
х
=1-
2
241.98
122
241.98 –122
х
=1
241.98
241.98
239.96
= 0.992 = 99.2%
241.98
Therefore degree of association of Benzoic acid is Benzene is 99.2 %
...
